Unique (old) Number System™
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(∑n)² = ∑n² + 2∑n
0 = 2*5*6*11/6 + 2∑n
∑n = - 55
0 = 2*5*6*11/6 + 2∑n
∑n = - 55
Forwarded from Ss...s.s. mm....
Find number of zero 5 ki power 10!
Unique (old) Number System™
Find number of zero 5 ki power 10!
There is no 2's so
0 trailing zeros
0 trailing zeros
Forwarded from °FSociety°
(2⁴ + 2⁸ + 2¹⁶ + 2⁷ + 2¹³ + 2^x)
(2² + 2⁴ + 2⁸)²
Compare
2¹¹
x = 11
(2² + 2⁴ + 2⁸)²
Compare
2¹¹
x = 11
Unique (old) Number System™
Can anyone solve this?
5¹⁰!
5⁹+5⁸+....+1
(5¹⁰-1) / 4 zeroes
5⁹+5⁸+....+1
(5¹⁰-1) / 4 zeroes
Unique (old) Number System™
Solution pls! @Bunny_6363 @Adonis_Babaa
25! mod 11³
11*22*{1*2*..10 * 12*13*..21 * 23*..25)
11²*2*(10!)³ mod 11³
121 { 2*1*(1*2*3)} mod 11
121 {12} mod 11
121 * 1 mod 11³
121
11*22*{1*2*..10 * 12*13*..21 * 23*..25)
11²*2*(10!)³ mod 11³
121 { 2*1*(1*2*3)} mod 11
121 {12} mod 11
121 * 1 mod 11³
121
Forwarded from Deleted Account
153 = 17*9
128⁵⁰⁰ / 9 = 2² = 4
128⁵⁰⁰ /17 = 9⁴ = 16
9a+4 = 17b + 16
67
128⁵⁰⁰ / 9 = 2² = 4
128⁵⁰⁰ /17 = 9⁴ = 16
9a+4 = 17b + 16
67
Similar pattern is observed in 1's
111..111..111 = multiple of 37
37 divisibility = 30a+7 Just summation.. so it shows magic
111..111..111 = multiple of 37
37 divisibility = 30a+7 Just summation.. so it shows magic
Unique (old) Number System™
Photo
2/3 * 10/11 = 20/33
250*20/33 ~ 151
33k ~ 500 = 495 k=15
33k ~ 750 = 726 k=22
20*7 = 140
1 to 24 = 24 - 24/3 - 24/7 - 24/21 = 24 - 8 - 3 - 1 = +12
1 to 5 = 5/3 = 1 -1
140 + 12 - 1 = 151
250*20/33 ~ 151
33k ~ 500 = 495 k=15
33k ~ 750 = 726 k=22
20*7 = 140
1 to 24 = 24 - 24/3 - 24/7 - 24/21 = 24 - 8 - 3 - 1 = +12
1 to 5 = 5/3 = 1 -1
140 + 12 - 1 = 151
Forwarded from Deleted Account
Only possibility for x is 4
44yy44 is square ..
44y = k²
K ~ 210
Y44 = 25x±12
k = 212
212² = 44944
4+9+4*9 = 49
xxyy = 7744 = 88²
3
44yy44 is square ..
44y = k²
K ~ 210
Y44 = 25x±12
k = 212
212² = 44944
4+9+4*9 = 49
xxyy = 7744 = 88²
3